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From: Byron Nash <byronnash@gmail.com>
Date: Thu, 18 Apr 2013 11:13:31 -0400
Message-ID: <CANGV+5qMJfAAZE9Dqr6MU6GFK5H83ecJAvnvFFO2avh8_EdxUg@mail.gmail.com>
Subject: Re: [AE] expressions: limiting decimals and adding 0 to single digit integers?
To: After Effects Mail List <AE-List@media-motion.tv>
Content-Type: multipart/alternative; boundary=089e0118306cd54c1c04daa40cb3

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Try doing a Round or floor mized with multiplying it by 100 to get a
predictable number of zeroes.

twoDigits = Math.round(num * 100) / 100;

Basically multiply your number by 100 for two zeroes and round it. Then
divide by 100 and you will have only two decimal places(rounded).


On Wed, Apr 17, 2013 at 2:34 AM, James Culbertson <albion@speakeasy.net>wrote:

> And is there a way to force the decimals to always be there even when they
> are XX.00 or XX.X0?
>
> Thanks,
>
> James
>
>
> On Apr 16, 2013, at 11:12 PM, Zack Lovatt wrote:
>
> From my understanding, this may be what you're looking for. Use this
> instead of your existing code. Doesn't deal with the negative sign, though;
> written hastily. In the morning I'll double check it and refine it to add
> the negative!
>
> nums = thisComp.layer("shape").transform.rotation.value.toFixed(2) + "";
>
> if ((nums < 10) && (nums > -10)) nums = "0" + nums;
>
> nums;
> I am linking one layers rotation to a text layers source text.
>
> How do I modify the simple expression to limit the decimal to two places,
> and at the same time make all integers two digits so 0 - 9 are 00, 01,
> 02,...?
>
> Something like this but that adds two decimal places to the number:
>
> //--Expression begins
> nums = thisComp.layer("shape").transform.rotation;
> amtOfZeroes = 2;
> //--Do not modify below this line
> isNeg = false;
> if(nums < 0)
> {
> nums = Math.abs( nums );
> isNeg = true;
> }
> sVal = Math.round( nums ) + "";
> while(sVal.length < amtOfZeroes)
> {
> sVal = "0" + sVal;
> }
> if(isNeg)
> sVal = "-" + sVal;
>
> sVal
> //--Expression ends
>
>
> Thanks, James
>
>
> +---End of message---+
> To unsubscribe send any message to <ae-list-off@media-motion.tv>
>
>
>

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<div dir=3D"ltr">Try doing a Round or floor mized with multiplying it by 10=
0 to get a predictable number of zeroes.=A0<div><br></div><div style>twoDig=
its =3D Math.round(num * 100) / 100;</div><div style><br></div><div style>B=
asically multiply your number by 100 for two zeroes and round it. Then divi=
de by 100 and you will have only two decimal places(rounded).=A0</div>

</div><div class=3D"gmail_extra"><br><br><div class=3D"gmail_quote">On Wed,=
 Apr 17, 2013 at 2:34 AM, James Culbertson <span dir=3D"ltr">&lt;<a href=3D=
"mailto:albion@speakeasy.net" target=3D"_blank">albion@speakeasy.net</a>&gt=
;</span> wrote:<br>

<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex"><div style=3D"word-wrap:break-word"><div>And=
 is there a way to force the decimals to always be there even when they are=
 XX.00 or XX.X0?</div>

<div><br></div><div>Thanks,</div><div><div class=3D"h5"><div><br></div><div=
>James</div><div><br></div><div><br></div><div><div>On Apr 16, 2013, at 11:=
12 PM, Zack Lovatt wrote:</div><br><blockquote type=3D"cite"><p dir=3D"ltr"=
>
From my understanding, this may be what you&#39;re looking for. Use this in=
stead of your existing code. Doesn&#39;t deal with the negative sign, thoug=
h; written hastily. In the morning I&#39;ll double check it and refine it t=
o add the negative!</p>

<p dir=3D"ltr">nums =3D thisComp.layer(&quot;shape&quot;).transform.rotatio=
n.value.toFixed(2) + &quot;&quot;;</p><p dir=3D"ltr">if ((nums &lt; 10) &am=
p;&amp; (nums &gt; -10)) nums =3D &quot;0&quot; + nums;</p><p dir=3D"ltr">n=
ums;</p>


<div style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex=
">I am linking one layers rotation to a text layers source text.<br>
<br>
How do I modify the simple expression to limit the decimal to two places, a=
nd at the same time make all integers two digits so 0 - 9 are 00, 01, 02,..=
.?<br>
<br>
Something like this but that adds two decimal places to the number:<br>
<br>
//--Expression begins<br>
nums =3D thisComp.layer(&quot;shape&quot;).transform.rotation;<br>
amtOfZeroes =3D 2;<br>
//--Do not modify below this line<br>
isNeg =3D false;<br>
if(nums &lt; 0)<br>
{<br>
nums =3D Math.abs( nums );<br>
isNeg =3D true;<br>
}<br>
sVal =3D Math.round( nums ) + &quot;&quot;;<br>
while(sVal.length &lt; amtOfZeroes)<br>
{<br>
sVal =3D &quot;0&quot; + sVal;<br>
}<br>
if(isNeg)<br>
sVal =3D &quot;-&quot; + sVal;<br>
<br>
sVal<br>
//--Expression ends<br>
<br>
<br>
Thanks, James<br>
<br>
<br>
+---End of message---+<br>
To unsubscribe send any message to &lt;<a href=3D"mailto:ae-list-off@media-=
motion.tv" target=3D"_blank">ae-list-off@media-motion.tv</a>&gt;<br>
</div>
</blockquote></div><br></div></div></div></blockquote></div><br></div>

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