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Subject: Re: [AE] expressions: limiting decimals and adding 0 to single digit integers?
From: James Culbertson <albion@speakeasy.net>
In-Reply-To: <list-5042845@media-motion.tv>
Date: Thu, 18 Apr 2013 10:36:52 -0700
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Message-Id: <355F5D8B-CB2B-4195-BAC7-8B47F9B8B13D@speakeasy.net>
References: <list-5042845@media-motion.tv>
To: "After Effects Mail List" <AE-List@media-motion.tv>

Thanks Byron,

Here's what finally worked:

// get the value we want
n =3D thisComp.layer("shape").transform.rotation.value;
// add two zeros, and make it an unsigned string -- we'll add the =
negative back later if it's supposed to be negative
nScaled =3D Math.abs(Math.round(n * 100));
s =3D "" +  nScaled.toString();
// pad low values with leading zeros to ensure at least 3 digits after =
we move the decimal point
while (s.length < 3)  s =3D "0" + s;
// if it was negative, add the - sign back
if (n<0) s =3D "-" + s;
// insert the decimal place before the last two decimal places
s =3D s.substr(0,s.length-2) + "." + s.substr(s.length-2,s.length)

Thanks to Walter Soyka over on the AE Creative Cow board.

James


On Apr 18, 2013, at 8:13 AM, Byron Nash wrote:

> Try doing a Round or floor mized with multiplying it by 100 to get a =
predictable number of zeroes.=20
>=20
> twoDigits =3D Math.round(num * 100) / 100;
>=20
> Basically multiply your number by 100 for two zeroes and round it. =
Then divide by 100 and you will have only two decimal places(rounded).=20=

>=20
>=20
> On Wed, Apr 17, 2013 at 2:34 AM, James Culbertson =
<albion@speakeasy.net> wrote:
> And is there a way to force the decimals to always be there even when =
they are XX.00 or XX.X0?
>=20
> Thanks,
>=20
> James
>=20
>=20
> On Apr 16, 2013, at 11:12 PM, Zack Lovatt wrote:
>=20
>> =46rom my understanding, this may be what you're looking for. Use =
this instead of your existing code. Doesn't deal with the negative sign, =
though; written hastily. In the morning I'll double check it and refine =
it to add the negative!
>>=20
>> nums =3D thisComp.layer("shape").transform.rotation.value.toFixed(2) =
+ "";
>>=20
>> if ((nums < 10) && (nums > -10)) nums =3D "0" + nums;
>>=20
>> nums;
>>=20
>> I am linking one layers rotation to a text layers source text.
>>=20
>> How do I modify the simple expression to limit the decimal to two =
places, and at the same time make all integers two digits so 0 - 9 are =
00, 01, 02,...?
>>=20
>> Something like this but that adds two decimal places to the number:
>>=20
>> //--Expression begins
>> nums =3D thisComp.layer("shape").transform.rotation;
>> amtOfZeroes =3D 2;
>> //--Do not modify below this line
>> isNeg =3D false;
>> if(nums < 0)
>> {
>> nums =3D Math.abs( nums );
>> isNeg =3D true;
>> }
>> sVal =3D Math.round( nums ) + "";
>> while(sVal.length < amtOfZeroes)
>> {
>> sVal =3D "0" + sVal;
>> }
>> if(isNeg)
>> sVal =3D "-" + sVal;
>>=20
>> sVal
>> //--Expression ends
>>=20
>>=20
>> Thanks, James
>>=20
>>=20
>> +---End of message---+
>> To unsubscribe send any message to <ae-list-off@media-motion.tv>
>=20
>=20