Return-Path: Received: from na3sys009aog126.obsmtp.com ([74.125.149.155] verified) by media-motion.tv (CommuniGate Pro SMTP 4.2.10) with SMTP id 5281402 for AE-List@media-motion.tv; Sun, 10 Nov 2013 00:03:00 +0100 Received: from mail-qa0-f41.google.com ([209.85.216.41]) (using TLSv1) by na3sys009aob126.postini.com ([74.125.148.12]) with SMTP ID DSNKUn6/hysSgTqCLb3HbyxiLLEPbhHGCciB@postini.com; Sat, 09 Nov 2013 15:04:41 PST Received: by mail-qa0-f41.google.com with SMTP id k4so759519qaq.14 for ; Sat, 09 Nov 2013 15:04:39 -0800 (PST) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=totaltraining.com; s=google; h=from:to:subject:date:content-type:in-reply-to:message-id :mime-version:reply-to:user-agent; bh=1Bi+i3kMIK0Tdep/u0I5pWt1ZqHQbyXhgtYN4MbVmQE=; b=OYpSnfgsUzwhf49byAhm5UpZHsM9YdsbuwUiHBOoH/XjqaVsYp+OHilQCYeBzkIgd/ Kd5H7eVif88zAp81Yv7jRPz9p4ud2KPTRSKpXBIUl4z3QTX0N82t0zAMPFFc7Jtnxurl IChodkqgB5DBEWJlOpPt7e5GwnUQcv3qAVAUY= X-Google-DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=1e100.net; s=20130820; h=x-gm-message-state:from:to:subject:date:content-type:in-reply-to :message-id:mime-version:reply-to:user-agent; bh=1Bi+i3kMIK0Tdep/u0I5pWt1ZqHQbyXhgtYN4MbVmQE=; b=TVwf0ATuTbRvUxve2uDBkOeWAyq211N4mcVxAcAkAwRupNVd1YUnbwX045O4g70pCR q4HjOnmiOW36y0NeJ8Dt+0VjUNgyQHTbwNKe7Rj9q4SX5TxJsDfnF19BHwsKWNHB9S6c BI3kxo8Z0gKiKQyLmwXfNP7ixigiFd22ICaneoDFC8bFLsJxK03jERVAHbD02QWJ+yrN 4t5k1HnxbbLiBrOXKwZ2kf7xVUsvzxxOOeEa0JLWvqp+/8DivPcB5QqNZGlemyyCtOU0 gyvdroQ5VDnKiqc7A021ud2TWlmzegzQY5x15HLiLGFunhDEpcx27r51xw3yevnwe/9u l/Ng== X-Gm-Message-State: ALoCoQnVdfXqKeGi470RJHldQpRiCPPzOASo2/3tOKCdxSkG88ArfsYpNc/+LhRFEuk4+Vydi4FvSW8CoCxVBiYHEEFIItQK90KWCB5YTLGzUmAWLlu0Kx4/my8CGLlAyhgDpBq5nCLTkmb9tlGeoQMKkqaM9pamQtNr/ZKUh8pzaM7Mx3XtDpc= X-Received: by 10.49.72.164 with SMTP id e4mr34501481qev.36.1384038279328; Sat, 09 Nov 2013 15:04:39 -0800 (PST) X-Received: by 10.49.72.164 with SMTP id e4mr34501479qev.36.1384038279258; Sat, 09 Nov 2013 15:04:39 -0800 (PST) Return-Path: Received: from [192.168.1.17] (pool-108-41-82-35.nycmny.fios.verizon.net. [108.41.82.35]) by mx.google.com with ESMTPSA id 4sm39390406qak.11.2013.11.09.15.04.38 for (version=TLSv1 cipher=ECDHE-RSA-AES128-SHA bits=128/128); Sat, 09 Nov 2013 15:04:38 -0800 (PST) From: brian@totaltraining.com To: "After Effects Mail List" Subject: Re[2]: [AE] Cell division graphic look Date: Sat, 09 Nov 2013 23:04:42 +0000 Content-Type: multipart/alternative; boundary="------=_MBEA3FA882-5C2A-412D-985B-EF330A1E6135" In-Reply-To: Message-Id: Mime-Version: 1.0 Reply-To: brian@totaltraining.com User-Agent: eM_Client/5.0.18661.0 --------=_MBEA3FA882-5C2A-412D-985B-EF330A1E6135 Content-Transfer-Encoding: quoted-printable Content-Type: text/plain; format=flowed; charset=utf-8 For smoothing edges like this, vector blur is your best friend. ------ Original Message ------ From: "croebot@gmail.com" To: "After Effects Mail List" Sent: 11/9/2013 6:00:10 PM Subject: Re: [AE] Cell division graphic look >Tim, this should get you going. You'll have to figure out how to smooth= =20 >the edges is the only problem. > >https://www.dropbox.com/s/xl51ov61rohtif0/cells.aep > > > >On Nov 9, 2013, at 2:23 PM, Tim Thiessen wrote: > >>Looking at that apple made in California video - got me thinking if=20 >>there is a trick to making it look like one circle is coming out of=20 >>another circle kind of like two cells where there is some material=20 >>between them until one breaks free. I seem to remember there was a=20 >>tutorial out there and I thought median was used - can anyone point me= =20 >>in the right direction? >> >>Thanks, >>Tim T >>+---End of message---+ >>To unsubscribe send any message to --------=_MBEA3FA882-5C2A-412D-985B-EF330A1E6135 Content-Transfer-Encoding: quoted-printable Content-Type: text/html; charset=utf-8
For smoothing edges like this, vector blur is your best friend.
 
------ Original Message ------
From: "croebot@gmail.com" <cro= ebot@gmail.com>
To: "After Effects Mail List" <AE-List@media-motion.tv>
Sent: 11/9/2013 6:00:10 PM
Subject: Re: [AE] Cell division graphic look
Tim, this should get you going. You'll have to figure out how to smoot= h the edges is the only problem. 


On Nov 9, 2013, at 2:23 PM, Tim Thiessen <pixelbot@comcast.net> wrote:

Looking at that apple made in California video - got me thinking= if there is a trick to making it look like one circle is coming out of = another circle kind of like two cells where there is some material between= them until one breaks free. I seem to remember there was a tutorial out= there and I thought median was used - can anyone point me in the right = direction?

Thanks,
Tim = T
+---End of message---+
To unsubscribe = send any message to <ae-l= ist-off@media-motion.tv>
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