You are better off making a string of numbers instead of an actual number that will naturally hit limits as you’ve found.

If you want random then this should work...

//——————————
var n = [“0”,”1”,”2”,”3”,”4”,”5”,”6”,”7”,”8”,”9”];
var nLen = n.length-1;
var len = 100; //Length of final number
var result = “”;
for(var i=0; i <= len; i++){
     result += n[Math.random(0, nLen)];
}

result;
//——————————

My random syntax might be off, but give that a try.


David Torno
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> On Sep 14, 2019, at 10:09 AM, Jim Curtis <AE-List@media-motion.tv> wrote:
>
> I’ve entered this expression on my Source Text applied to “999999999999”.
>
> Math.round(random(99999999999999999999999999999999999999)*99999999999)
>
> At a certain point, Ae returns an exponential value, like “...99999e +48”
>
> What I’m trying to get is a really loooooonnng string of animating random numbers with no decimal points.
>
> What am I doing wrong?  I’m an expression dummy.
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>


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